If f(x) = x3 \(\frac{1}{x^3}\), then show that f(x) f(\(\frac{1}{x}\)) = 0 Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries a) The function f(x) = 1/2x^4x^3x3 is continuous Now f(2) = 1 and f(25) = Since f(2) and f(25) have opposite signs, according to the intermediate value theorem, there is at least one root of f(x)=0 between 2 and 25 An interval like 2,25, where a continuous function takes different signs at the two endpoints, is called a bracketing interval In both theSolution Steps f ( x ) = x ^ { 3 } 6 x 7 \text { at } x = 2 f ( x) = − x 3 6 x − 7 at x = 2 Consider the first equation Insert the known values of variables into the equation Consider the first equation Insert the known values of variables into the equation f\times 2=2^ {3}6\times 27 f × 2 = − 2 3
The Function F X X 3 X 1 F X X 2 4 3x 2 13 4 X 1 Is Sarthaks Econnect Largest Online Education Community